Which of the following is the equation a superscript left parenthesis 2 b plus 1 right parenthesis baseline equals 3 c minus d written in logarithmic form?

(1 point)
Responses

log subscript a baseline left parenthesis 3 c minus d right parenthesis equals 2 b plus 1
Image with alt text: log subscript a baseline left parenthesis 3 c minus d right parenthesis equals 2 b plus 1

log subscript a baseline left parenthesis 2 b plus 1 right parenthesis equals 3 c minus d
Image with alt text: log subscript a baseline left parenthesis 2 b plus 1 right parenthesis equals 3 c minus d

log subscript left parenthesis 2 b plus 1 right parenthesis baseline a equals 3 c minus d
Image with alt text: log subscript left parenthesis 2 b plus 1 right parenthesis baseline a equals 3 c minus d

log subscript left parenthesis 2 b plus 1 right parenthesis baseline 3 c minus d equals a
Image with alt text: log subscript left parenthesis 2 b plus 1 right parenthesis baseline 3 c minus d equals a

1 answer

To rewrite the equation \( a^{(2b + 1)} = 3c - d \) in logarithmic form, we can use the definition of a logarithm which states that if \( a^x = y \), then \( \log_a(y) = x \).

In this case, we can identify:

  • \( a \) as the base,
  • \( 2b + 1 \) as the exponent,
  • \( 3c - d \) as the resultant value.

Using this information, we can convert the equation into logarithmic form:

\[ \log_a(3c - d) = 2b + 1 \]

Therefore, the correct answer from the choices given is:

log subscript a baseline left parenthesis 3 c minus d right parenthesis equals 2 b plus 1.

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