Which of the following is not a value of θ when sin θ=−1 ?(1 point) Responses 3π2 Start Fraction 3 pi over 2 End Fraction π pi −π2 negative Start Fraction pi over 2 End Fraction 7π2

1 answer

To determine which of the given options is not a value of \( \theta \) when \( \sin \theta = -1 \), we first need to understand the conditions under which \( \sin \theta = -1 \).

The sine function equals -1 at:

\[ \theta = \frac{3\pi}{2} + 2k\pi \]

where \( k \) is any integer (because the sine function has a period of \( 2\pi \)).

Now let's evaluate each of the provided options:

  1. \( \frac{3\pi}{2} \) – This is a value where \( \sin \theta = -1 \).
  2. \( \pi \) – This does not equal -1 for the sine function.
  3. \( -\frac{\pi}{2} \) – This does not equal -1 for the sine function.
  4. \( \frac{7\pi}{2} \) – This can be simplified as \( \frac{7\pi}{2} = \frac{3\pi}{2} + 2\pi \), so it does equal -1 for the sine function.
  5. \( \pi \) again, as stated before, does not equal -1.

From this analysis, the options that do not yield \( \sin \theta = -1 \) are:

  • \( \pi \)
  • \( -\frac{\pi}{2} \)

Thus, out of the choices provided, \( \pi \) is one of the definite answers.

Therefore, the option that is not a value of \( \theta \) when \( \sin \theta = -1 \) is:

\[ \pi \]