just expand each product, and see whether all the terms are divisible by 6.
For example,
(2n+3)(3n+2) = 6n^2+13n+6
You can see that 13n is not necessarily divisible by 6.
If you expand the others, you will see that one of them has all its terms multiples of 6.
Which of the following is divisible by 6 when n is any integer?
A. (2n+3)(3n+2)
B. n(n+1)(n+2)
C. (2n+3)(3n-2)
D. n(n+2)(3n+6)
1 answer
1 answer