Let's address each question one by one.
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Irrational number between 5 and 7
We need to analyze the given numbers:
- \( 6 - \sqrt{2} \)
- \( \sqrt{12} \)
- \( \sqrt{27} \)
- \( \sqrt{36} = 6 \) (which is not irrational)
Let's evaluate the irrational values:
- \( 6 - \sqrt{2} \) is irrational, and \( \sqrt{2} \approx 1.414 \), so \( 6 - \sqrt{2} \approx 4.586 \) (not between 5 and 7).
- \( \sqrt{12} \approx 3.464 \) (not between 5 and 7).
- \( \sqrt{27} \approx 5.196 \) (this is between 5 and 7).
- \( \sqrt{36} = 6 \) (not irrational).
Therefore, the answer is \( \sqrt{27} \approx 5.196 \).
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Largest integer whose square root is an irrational number between 3 and 4
We want to find an integer \( n \) such that \( 3 < \sqrt{n} < 4 \).
- Squaring the inequalities gives \( 9 < n < 16 \).
The largest integer \( n \) in this range is 15.
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Rational number between 2 and \( 2 \frac{1}{4} \)
To find a rational number between 2 and \( 2 \frac{1}{4} \), first convert \( 2 \frac{1}{4} \) to an improper fraction:
- \( 2 \frac{1}{4} = \frac{9}{4} \).
Now, we can find a rational number by adding 2 and \( 2 \frac{1}{4} \) together and dividing by 2: \[ \text{Average} = \frac{2 + 2 \frac{1}{4}}{2} = \frac{2 + \frac{9}{4}}{2} = \frac{\frac{8}{4} + \frac{9}{4}}{2} = \frac{\frac{17}{4}}{2} = \frac{17}{8} = 2 \frac{1}{8}. \] Therefore, a rational number between 2 and \( 2 \frac{1}{4} \) is \( 2 \frac{1}{8} \).
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Rational number with one decimal place between \( \sqrt{17} \) and \( \sqrt{18} \)
First, we compute:
- \( \sqrt{17} \approx 4.123 \)
- \( \sqrt{18} \approx 4.243 \)
A rational number with one decimal place that is between these values could be 4.2.
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Which of the following is between \( \pi \) and \( \sqrt{11} \)
Approximate the values:
- \( \pi \approx 3.141 \)
- \( \sqrt{11} \approx 3.317 \)
Analyze the options:
- \( \sqrt{7} \approx 2.646 \) (not between).
- \( \sqrt{8} \approx 2.828 \) (not between).
- \( \sqrt{12} \approx 3.464 \) (not between).
- \( \sqrt{10} \approx 3.162 \) (this is between \( \pi \) and \( \sqrt{11} \)).
Therefore, the answer is \( \sqrt{10} \).