To determine which of the given options is an irrational number between 5 and 7, we can evaluate each option:
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\( 6 - \sqrt{6} \): First, we can approximate: \[ \sqrt{6} \approx 2.45 \quad (\text{since } 2.45^2 \approx 6) \] Therefore: \[ 6 - \sqrt{6} \approx 6 - 2.45 = 3.55 \quad (\text{which is not between 5 and 7}) \]
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\( \sqrt{12} \): We can simplify this as follows: \[ \sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3} \] Approximating \( \sqrt{3} \): \[ \sqrt{3} \approx 1.73 \Rightarrow 2\sqrt{3} \approx 2 \cdot 1.73 = 3.46 \quad (\text{which is not between 5 and 7}) \]
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\( \sqrt{27} \): We have: \[ \sqrt{27} = \sqrt{9 \cdot 3} = 3\sqrt{3} \] Approximating \( \sqrt{3} \): \[ \sqrt{3} \approx 1.73 \Rightarrow 3\sqrt{3} \approx 3 \cdot 1.73 = 5.19 \quad (\text{which is between 5 and 7}) \]
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\( \sqrt{36} \): This can be simplified easily: \[ \sqrt{36} = 6 \quad (\text{which is not between 5 and 7, but exactly 6}) \]
The only irrational number between 5 and 7 among the provided options is:
\[ \sqrt{27} \]
Thus, the answer is \( \sqrt{27} \) (which is approximately 5.196).