To evaluate the expression \( \frac{1}{2}(9 - 7^0) + (-29)^0 \), we can simplify it step by step.
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First, calculate \( 7^0 \). Any non-zero number raised to the power of \( 0 \) is \( 1 \). So, \( 7^0 = 1 \).
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Now replace \( 7^0 \) in the expression: \[ \frac{1}{2}(9 - 1) + (-29)^0 \]
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Next, calculate \( (-29)^0 \). Again, any non-zero number raised to the power of \( 0 \) is \( 1 \). Thus, \( (-29)^0 = 1 \).
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Substituting this back into the expression, we have: \[ \frac{1}{2}(9 - 1) + 1 \]
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Simplify \( 9 - 1 \): \[ 9 - 1 = 8 \]
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Now calculate \( \frac{1}{2} \times 8 \): \[ \frac{1}{2}(8) = 4 \]
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Finally, add \( 4 + 1 \): \[ 4 + 1 = 5 \]
Now let's check the provided options for the equivalent expression:
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Option 1: \( 1^2(2) + 1 = 1 \cdot 2 + 1 = 2 + 1 = 3\) (not equivalent)
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Option 2: \( \frac{1}{2}(9 - 0) + 0 = \frac{1}{2}(9) + 0 = 4.5 + 0 = 4.5\) (not equivalent)
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Option 3: \( 1^2(9 - 1) + 1 = 1 \cdot (9 - 1) + 1 = 1 \cdot 8 + 1 = 8 + 1 = 9\) (not equivalent)
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Option 4: \( 1^2(9 - 1) - 1 = 1 \cdot (9 - 1) - 1 = 1 \cdot 8 - 1 = 8 - 1 = 7\) (not equivalent)
It turns out that none of the provided options equal \( 5\). Therefore, none of the responses are equivalent to the given expression \( \frac{1}{2}(9 - 7^0) + (-29)^0\).