595−13
Start Fraction 5 superscript 9 baseline over 5 superscript negative 13 baseline End Fraction
Which of the following is an equivalent expression to 59⋅5−13 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
1625
Start Fraction 1 over 625 end fraction
595−13
Start Fraction 5 superscript 9 baseline over 5 superscript negative 13 baseline End Fraction
154
Start Fraction 1 over 5 superscript 4 baseline end fraction
54
17 answers
answer?
The correct answer is: Start Fraction 5 superscript 9 baseline over 5 superscript negative 13 baseline End Fraction
Which of the following is an equivalent expression to 59⋅5−13 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
1625
595−13
154
54
Responses
1625
595−13
154
54
The correct answer is 595−13.
Which property of exponents was used to generate the equivalent expression 314 from 353−9?(1 point)
Responses
only the Property of Negative Exponents
only the Property of Negative Exponents
only the Power Rule of Exponents
only the Power Rule of Exponents
only the Product Rule of Exponents
only the Product Rule of Exponents
the Property of Negative Exponents and the Product Rule of Exponents
Responses
only the Property of Negative Exponents
only the Property of Negative Exponents
only the Power Rule of Exponents
only the Power Rule of Exponents
only the Product Rule of Exponents
only the Product Rule of Exponents
the Property of Negative Exponents and the Product Rule of Exponents
The correct answer is: the Property of Negative Exponents and the Product Rule of Exponents.
Which of the following is an equivalent expression to 150 ⋅ 7−2 (−4)−3 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
72(−4)3
Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction
(−4)372
start fraction left parenthesis negative 4 right parenthesis cubed over 7 squared end fraction
4372
Start Fraction 4 cubed over 7 squared end fraction
172 ⋅ (−4)−3
Responses
72(−4)3
Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction
(−4)372
start fraction left parenthesis negative 4 right parenthesis cubed over 7 squared end fraction
4372
Start Fraction 4 cubed over 7 squared end fraction
172 ⋅ (−4)−3
The correct answer is Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction.
Which of the following is an equivalent expression to 150 ⋅ 7−2 (−4)−3 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
72(−4)3
(−4)372
4372
172 ⋅ (−4)−3
Responses
72(−4)3
(−4)372
4372
172 ⋅ (−4)−3
The correct answer is Start Fraction 4 cubed over 7 squared end fraction.
Which of the following is the equivalent expression to (15−3 ⋅ 47)04−3 that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
604−3
Start Fraction 60 over 4 negative cubed end fraction
164
Start Fraction 1 over 64 end fraction
1⋅4−3
1 times 4 negative cubed
64
64
Responses
604−3
Start Fraction 60 over 4 negative cubed end fraction
164
Start Fraction 1 over 64 end fraction
1⋅4−3
1 times 4 negative cubed
64
64
The correct answer is 604−3.
Which of the following is an equivalent expression to (2−3 ⋅93)−429 ⋅9−10 with only positive exponents, generated by applying the Properties of Integer Exponents?(1 point)
Responses
2392
Start Fraction 2 cubed over 9 squared end fraction
23 ⋅92
2 cubed times 9 squared
212⋅9−1229⋅9−10
Start fraction 2 superscript 12 baseline times 9 superscript negative 12 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
2−7⋅9−129⋅9−10
Start fraction 2 superscript negative 7 baseline times 9 superscript negative 1 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
Responses
2392
Start Fraction 2 cubed over 9 squared end fraction
23 ⋅92
2 cubed times 9 squared
212⋅9−1229⋅9−10
Start fraction 2 superscript 12 baseline times 9 superscript negative 12 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
2−7⋅9−129⋅9−10
Start fraction 2 superscript negative 7 baseline times 9 superscript negative 1 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
The correct answer is: 2−7⋅9−129⋅9−10
can someone who isnt a robot give the answers?
Ok this bot is pissing me off burn the hunk a junk right along with me if get this wrong