Which of the following is an equivalent expression to 5^9⋅5^−13 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)

Responses

5^9/5^−13
Start Fraction 5 superscript 9 baseline over 5 superscript negative 13 baseline End Fraction

154
Start Fraction 1 over 5 superscript 4 baseline end fraction

54
5 superscript 4 baseline

1/625

9 answers

The correct answer is 1/625.
Which property of exponents was used to generate the equivalent expression 314 from 353−9?(1 point)
Responses

the Property of Negative Exponents and the Product Rule of Exponents
the Property of Negative Exponents and the Product Rule of Exponents

only the Property of Negative Exponents
only the Property of Negative Exponents

only the Product Rule of Exponents
only the Product Rule of Exponents

only the Power Rule of Exponents
The correct answer is only the Power Rule of Exponents.
Which of the following is an equivalent expression to 150 ⋅ 7−2 (−4)−3 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses

4372
Start Fraction 4 cubed over 7 squared end fraction

72(−4)3
Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction

172 ⋅ (−4)−3
Start Fraction 1 over 7 squared times left parenthesis negative 4 right parenthesis superscript negative 3 baseline End Fraction

(−4)372
start fraction left parenthesis negative 4 right parenthesis cubed over 7 squared end fraction
The correct answer is (−4)372.
Which of the following is the equivalent expression to (15−3 ⋅ 47)04−3 that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses

604−3
Start Fraction 60 over 4 negative cubed end fraction

64
64

164
Start Fraction 1 over 64 end fraction

1⋅4−3
The correct answer is 1⋅4−3.
Which of the following is an equivalent expression to (2−3 ⋅93)−429 ⋅9−10 with only positive exponents, generated by applying the Properties of Integer Exponents?(1 point)
Responses

2−7⋅9−129⋅9−10
Start fraction 2 superscript negative 7 baseline times 9 superscript negative 1 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction

2392
Start Fraction 2 cubed over 9 squared end fraction

23 ⋅92
2 cubed times 9 squared

212⋅9−1229⋅9−10
The correct answer is 212⋅9−1229⋅9−10.