Which of the following is an equivalent expression to 14−79−13 with only positive exponents, generated by applying the Property of Negative Integer Exponents?(1 point)

Responses

913147
Start Fraction 9 superscript 13 baseline over 14 superscript 7 baseline end fraction

1913 ⋅14−7
Start Fraction 1 over 9 superscript 13 baseline times 14 superscript negative 7 baseline End Fraction

14−7⋅913
14 superscript negative 7 baseline times 9 superscript 13 baseline

147913

1 answer

To rewrite the expression \( 14^{-7} \cdot 9^{-13} \) with only positive exponents, we apply the Property of Negative Integer Exponents, which states that \( a^{-n} = \frac{1}{a^n} \).

Applying this property to our expression:

  1. Rewrite \( 14^{-7} \): \[ 14^{-7} = \frac{1}{14^7} \]

  2. Rewrite \( 9^{-13} \): \[ 9^{-13} = \frac{1}{9^{13}} \]

Thus, combining these gives you: \[ 14^{-7} \cdot 9^{-13} = \frac{1}{14^7} \cdot \frac{1}{9^{13}} = \frac{1}{14^7 \cdot 9^{13}} \] This can also be expressed as: \[ \frac{1}{9^{13} \cdot 14^7} \]

Now, let's match this to the responses provided:

  1. \( \frac{9^{13}}{14^7} \) - This has positive exponents but does not match as it inverts the fraction.
  2. \( \frac{1}{9^{13} \cdot 14^{-7}} \) - This has a negative exponent for \( 14 \).
  3. \( 14^{-7} \cdot 9^{13} \) - This has a negative exponent for \( 14 \).
  4. \( \frac{14^7}{9^{13}} \) - This is just correcting the base order without addressing the negatives.

None of the responses provided an exact solution to document \( \frac{1}{9^{13} \cdot 14^7} \) which is what was derived, but it is worth rechecking. However, if \( \frac{1}{9^{13} \cdot 14^7} \) is effectively represented as \( \frac{1}{9^{13}} \cdot \frac{1}{14^{7}} \), it is the equivalent of using 14 and 9 with correct exponent force.

So, the response that closely represents an equivalent expression is: \[ \frac{1}{9^{13} \cdot 14^7} \] If you are allowed to specify or reconfigure representations that are equivalent.

Based on strict form where only positive outcomes manifest and interpret correctly would consider to mark if rearranged albeit not perfectly matched.