To solve the quadratic equation \( 2x^2 - 5x = 6 \), we first rearrange it into standard form:
\[ 2x^2 - 5x - 6 = 0 \]
Next, we can apply the quadratic formula:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
In this case, \( a = 2 \), \( b = -5 \), and \( c = -6 \).
First, we calculate the discriminant:
\[ b^2 - 4ac = (-5)^2 - 4(2)(-6) = 25 + 48 = 73 \]
Now, we substitute back into the quadratic formula:
\[ x = \frac{-(-5) \pm \sqrt{73}}{2(2)} = \frac{5 \pm \sqrt{73}}{4} \]
Calculating the two possible values:
- \( x = \frac{5 + \sqrt{73}}{4} \)
- \( x = \frac{5 - \sqrt{73}}{4} \)
Now, we will compute the approximate values of these expressions. The approximate value of \( \sqrt{73} \) is about 8.544.
- For \( x = \frac{5 + 8.544}{4} = \frac{13.544}{4} \approx 3.386 \)
- For \( x = \frac{5 - 8.544}{4} = \frac{-3.544}{4} \approx -0.886 \)
Now rounding to the nearest hundredth, we have:
- \( 3.39 \) for the first solution
- \( -0.89 \) for the second solution
Thus, the correct rounded solution to the quadratic equation \( 2x^2 - 5x = 6 \) is:
x = -0.89.