To solve the quadratic equation -x^2+x=-10, we can rewrite it as -x^2+x+10=0.
Next, we can either apply the quadratic formula or factor the equation.
Applying the quadratic formula:
The quadratic formula is x = (-b ± √(b^2-4ac))/(2a).
In this case, a=-1, b=1, and c=10.
Plugging in these values, we get:
x = (-1 ± √(1^2-4(-1)(10)))/(2(-1))
= (-1 ± √(1+40))/(-2)
= (-1 ± √41)/(-2)
Rounding this to the nearest hundredth, we have the two solutions:
x ≈ 4.29 and x ≈ -0.29
Therefore, the correct solution rounded to the nearest hundred is x ≈ -0.29.
which of the following is a solution to the quadratic equation -x^2+x=-10? assume that the solution has been rounded to the nearest hundred
3 answers
out of x=.27, x=3.7, x=1.7, x=.77
None of the given options (x = 0.27, x = 3.7, x = 1.7, x = 0.77) are solutions to the quadratic equation -x^2 + x = -10.