The quadratic equation −x^2+x=−10 can be rewritten as −x^2+x+10=0. To find the solution(s) to this equation, we can use the quadratic formula: x = [-b ± sqrt(b^2-4ac)] / 2a.
In this case, a = -1, b = 1, and c = 10. Plugging these values into the quadratic formula, we get:
x = [-(1) ± sqrt((1)^2-4(-1)(10))] / 2(-1)
x = [-1 ± sqrt(1+40)] / -2
x = [-1 ± sqrt(41)] / -2
Rounding to the nearest hundredth, the solutions are:
x ≈ -4.56 and x ≈ 3.56
Therefore, the solutions to the quadratic equation −x^2+x=−10 are approximately -4.56 and 3.56.
Which of the following is a solution to the quadratic equation −x^2+x=−10
? Assume that the solution has been rounded to the nearest hundredth, if applicable.
1 answer
1 answer