To find the solutions to the quadratic equation −x^2+x=−10, we need to set the equation equal to 0:
−x^2+x+10=0
Next, we can solve this equation using the quadratic formula:
x = (-b ± √(b^2-4ac))/(2a)
In this equation, a = -1, b = 1, and c = 10. Substituting these values into the quadratic formula, we have:
x = (-(1) ± √((1)^2-4(-1)(10)))/(2(-1))
x = (-1 ± √(1+40))/(-2)
x = (-1 ± √41)/(-2)
Rounded to the nearest hundredth, the solutions are approximately x = 0.77 and x = -2.77. Therefore, the correct solution from the given options is x = 0.77.
Which of the following is a solution to the quadratic equation −x2+x=−10 ? Assume that the solution has been rounded to the nearest hundredth, if applicable.(1 point) Responses x=0.77 x equals 0.77 x=0.27 x equals 0.27 x=1.7 x equals 1.7 x=3.7 x equals 3.7
1 answer