Which of the following is a solution of x² + 14x + 112 = 0? If necessary, round to the nearest hundredth.

Answer 1

To find the solutions of the quadratic equation x² + 14x + 112 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

In this equation, the coefficients are:
a = 1, b = 14, c = 112

Plugging these values into the quadratic formula, we get:

x = (-14 ± √(14² - 4*1*112)) / 2*1
x = (-14 ± √(196 - 448)) / 2
x = (-14 ± √(-252)) / 2

Since the discriminant (-252) is negative, the solutions will be imaginary. Therefore, there are no real solutions to the equation x² + 14x + 112 = 0.