To solve the logarithmic equation \( \ln(2 - 3x) = \ln(-5x) \), we can start by setting the arguments of the natural logarithm equal to each other, given that the natural logarithm is a one-to-one function:
\[ 2 - 3x = -5x \]
Next, we solve for \( x \):
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Add \( 3x \) to both sides: \[ 2 = -5x + 3x \] \[ 2 = -2x \]
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Divide both sides by -2: \[ x = -1 \]
Now, we need to check if this solution is valid by ensuring that the arguments of the logarithms are positive:
- Substitute \( x = -1 \) back into the arguments:
- For \( 2 - 3(-1) \): \[ 2 + 3 = 5 \quad (\text{which is positive}) \]
- For \( -5(-1) \): \[ 5 \quad (\text{which is also positive}) \]
Since both arguments are positive, \( x = -1 \) is a valid solution.
- Now let's check the other provided options for validity:
- \( x = 1 \):
- \( 2 - 3(1) = -1 \) (not valid)
- \( -5(1) = -5 \) (not valid)
- \( x = -3 \):
- \( 2 - 3(-3) = 11 \) (valid)
- \( -5(-3) = 15 \) (valid)
- \( x = 3 \):
- \( 2 - 3(3) = -7 \) (not valid)
- \( -5(3) = -15 \) (not valid)
- \( x = 1 \):
The only reasonable solution in the context of the options given is:
\( x = -1 \).