To complete the table for the quadratic equation \(y = -6x^2 + 3x + 8\), we will evaluate the function \(y\) for the missing \(x\) values.
Given data:
-
\(x = -1\):
\[
y = -6(-1)^2 + 3(-1) + 8 = -6(1) - 3 + 8 = -6 - 3 + 8 = -1
\]
So, \((-1, -1)\) completes the table.
-
\(x = -0.75\):
\[
y = -6(-0.75)^2 + 3(-0.75) + 8 = -6(0.5625) - 2.25 + 8 = -3.375 - 2.25 + 8 = 2.375
\]
So, \((-0.75, 2.375)\) completes the table.
-
\(x = -0.5\):
\[
y = -6(-0.5)^2 + 3(-0.5) + 8 = -6(0.25) - 1.5 + 8 = -1.5 - 1.5 + 8 = 5
\]
So, \((-0.5, 5)\) completes the table.
-
\(x = -0.25\):
\[
y = -6(-0.25)^2 + 3(-0.25) + 8 = -6(0.0625) - 0.75 + 8 = -0.375 - 0.75 + 8 = 6.875
\]
So, \((-0.25, 6.875)\) completes the table.
-
\(x = 0.5\):
\[
y = -6(0.5)^2 + 3(0.5) + 8 = -6(0.25) + 1.5 + 8 = -1.5 + 1.5 + 8 = 8
\]
So, \((0.5, 8)\) completes the table.
-
\(x = 0.75\):
\[
y = -6(0.75)^2 + 3(0.75) + 8 = -6(0.5625) + 2.25 + 8 = -3.375 + 2.25 + 8 = 6.875
\]
So, \((0.75, 6.875)\) completes the table.
-
\(x = 1\):
\[
y = -6(1)^2 + 3(1) + 8 = -6 + 3 + 8 = 5
\]
So, \((1, 5)\) is already provided.
Completed Table
- For \(x = -1\), \(y = -1\).
- For \(x = -0.75\), \(y = 2.375\).
- For \(x = -0.5\), \(y = 5\).
- For \(x = -0.25\), \(y = 6.875\).
- For \(x = 0\), \(y = 8\).
- For \(x = 0.25\), \(y = 8.375\).
- For \(x = 0.5\), \(y = 8\).
- For \(x = 0.75\), \(y = 6.875\).
- For \(x = 1\), \(y = 5\).
Finding the High or Low Point
Since the quadratic opens downwards (the coefficient of \(x^2\) is negative), the vertex will be the maximum point (high point) of the parabola.
To find the vertex \(x\)-coordinate:
\[
x = -\frac{b}{2a} = -\frac{3}{2(-6)} = \frac{3}{12} = 0.25
\]
Now plug \(x = 0.25\) back into the equation to find \(y\):
\[
y = -6(0.25)^2 + 3(0.25) + 8 = -6(0.0625) + 0.75 + 8 = -0.375 + 0.75 + 8 = 8.375
\]
So, the vertex (high point) is \((0.25, 8.375)\).
Response Conclusion
Among the responses given:
- (0.25, 8.375) is the correct one.