To determine which point lies on the parabola defined by the quadratic equation \( y = -6x^2 + 3x + 8 \), we can substitute the x-coordinates of each option into the equation and see if the resulting y-value matches the given y-coordinate.
Let's evaluate the equation with each x-coordinate provided.
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For the point \((-3, -55)\): \[ y = -6(-3)^2 + 3(-3) + 8 = -6(9) - 9 + 8 = -54 - 9 + 8 = -55 \] This point works.
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For the point \((-6, 206)\): \[ y = -6(-6)^2 + 3(-6) + 8 = -6(36) - 18 + 8 = -216 - 18 + 8 = -226 \] This does not match.
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For the point \((-3, 323)\): We already found that \((-3, -55)\) works, so we will not check this one since \(-55 \neq 323\).
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For the point \((-6, 8)\): We found that for \(x = -6\), \(y\) evaluates to \(-226\), which is not 8.
The only point that satisfies the equation \( y = -6x^2 + 3x + 8 \) is \((-3, -55)\).
Thus, the answer is: \((-3, -55)\).