Which of the following is a point you can generate to create the parabola for the quadratic equation: y = -6x^2 + 3x + 8

Answer 1

To generate points to create the parabola for the quadratic equation $y=-6x^2+3x+8$, you can choose different values for $x$ and calculate the corresponding $y$ values. Here are a few values of $x$ and their corresponding $y$:

1. When $x=0$: $$y=-6(0{)}^2+3(0)+8=8\text{(Point: (0, 8))}$$

2. When $x=1$: $$y=-6(1{)}^2+3(1)+8=-6+3+8=5\text{(Point: (1, 5))}$$

3. When $x=-1$: $$y=-6(-1{)}^2+3(-1)+8=-6-3+8=-1\text{(Point: (-1, -1))}$$

4. When $x=2$: $$y=-6(2{)}^2+3(2)+8=-24+6+8=-10\text{(Point: (2, -10))}$$

5. When $x=-2$: $$y=-6(-2{)}^2+3(-2)+8=-24-6+8=-22\text{(Point: (-2, -22))}$$

You can continue to calculate more points to get a better graph of the parabola. The points generated above include:

1. (0, 8)
2. (1, 5)
3. (-1, -1)
4. (2, -10)
5. (-2, -22)

These points should help in plotting the parabola defined by the quadratic equation.