To determine which point is on the graph of the function \( y = (2x + 1)^2 - 4 \), we can substitute the x-coordinates of the given points into the function and see if we get the corresponding y-coordinates.
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For the point \( (1, 2) \): \[ y = (2(1) + 1)^2 - 4 = (2 + 1)^2 - 4 = 3^2 - 4 = 9 - 4 = 5 \] This point does not lie on the graph since \( 5 \neq 2 \).
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For the point \( (0, -2) \): \[ y = (2(0) + 1)^2 - 4 = (0 + 1)^2 - 4 = 1^2 - 4 = 1 - 4 = -3 \] This point does not lie on the graph since \( -3 \neq -2 \).
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For the point \( (-1, -5) \): \[ y = (2(-1) + 1)^2 - 4 = (-2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3 \] This point does not lie on the graph since \( -3 \neq -5 \).
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For the point \( (-1, -3) \): \[ y = (2(-1) + 1)^2 - 4 = (-2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3 \] This point lies on the graph since \( -3 = -3 \).
Therefore, the point that is on the graph is \( (-1, -3) \).