Which of the following is a point on the graph as described by the function y=(2x+1)2−4

y
=
(
2
x
+
1
)
2

4
?(1 point)
Responses

(−1,−3)
(

1
,

3
)
left parenthesis negative 1 comma negative 3 right parenthesis

(0,−2)
(
0
,

2
)
left parenthesis 0 comma negative 2 right parenthesis

(−1,−5)
(

1
,

5
)
left parenthesis negative 1 comma negative 5 right parenthesis

(1,2)
(
1
,
2
)

1 answer

To determine which of the given points lies on the graph of the function \( y = (2x + 1)^2 - 4 \), we will evaluate the function for each x-coordinate in the options provided and see if the resulting y-coordinate matches any of the given points.

  1. For \( x = -1 \): \[ y = (2(-1) + 1)^2 - 4 = (-2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3 \] So the point \((-1, -3)\) is on the graph.

  2. For \( x = 0 \): \[ y = (2(0) + 1)^2 - 4 = (0 + 1)^2 - 4 = 1^2 - 4 = 1 - 4 = -3 \] So the point \((0, -2)\) is NOT on the graph.

  3. For \( x = -1 \) (already calculated): We already computed this and found that \( y = -3 \), confirming that \((-1, -3)\) is on the graph.

  4. For \( x = 1 \): \[ y = (2(1) + 1)^2 - 4 = (2 + 1)^2 - 4 = 3^2 - 4 = 9 - 4 = 5 \] So the point \((1, 2)\) is NOT on the graph.

After evaluating all options, we find that the only point that matches is \((-1, -3)\).

Answer: \((-1, -3)\)