To determine which of the given points lies on the graph of the function \( y = (2x + 1)^2 - 4 \), we will evaluate the function for each x-coordinate in the options provided and see if the resulting y-coordinate matches any of the given points.
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For \( x = -1 \): \[ y = (2(-1) + 1)^2 - 4 = (-2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3 \] So the point \((-1, -3)\) is on the graph.
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For \( x = 0 \): \[ y = (2(0) + 1)^2 - 4 = (0 + 1)^2 - 4 = 1^2 - 4 = 1 - 4 = -3 \] So the point \((0, -2)\) is NOT on the graph.
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For \( x = -1 \) (already calculated): We already computed this and found that \( y = -3 \), confirming that \((-1, -3)\) is on the graph.
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For \( x = 1 \): \[ y = (2(1) + 1)^2 - 4 = (2 + 1)^2 - 4 = 3^2 - 4 = 9 - 4 = 5 \] So the point \((1, 2)\) is NOT on the graph.
After evaluating all options, we find that the only point that matches is \((-1, -3)\).
Answer: \((-1, -3)\)