To find the point on the graph as described by the function y = (2x + 1)^2 - 4, we need to substitute the x-values in the equation and then find the corresponding y-values.
Checking each option by substituting the x-values:
A. (0,-2)
y = (2(0) + 1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3 (not -2)
So, option A is not correct.
B. (1,2)
y = (2(1) + 1)^2 - 4
y = (3)^2 - 4
y = 9 - 4
y = 5 (not 2)
So, option B is not correct.
C. (-1,-5)
y = (2(-1) + 1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3 (not -5)
So, option C is not correct.
D. (-1,-3)
y = (2(-1) + 1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3
So, option D is correct.
Therefore, the point on the graph as described by the function is (-1,-3), which corresponds to option D.
Which of the following is a point on the graph as described by the function y = (2x + 1)^2 - 4?
A. (0,-2)
B. (1,2)
C. (-1,-5)
D. (-1,-3)
1 answer
1 answer