Question

Which of the following is a point on the graph as described by the function y=(2x+1)2−4 ?

(-1, -5)
(-1, -3)
(0, -2)
(1, 2)

Answer 1

To find the point(s) on the graph of the function, we substitute the x-values into the function equation.

For (-1, -5), substitute x = -1 into the equation:
y = (2(-1) + 1)^2 - 4
y = ( -2 + 1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3

For (-1, -3), substitute x = -1 into the equation:
y = (2(-1) + 1)^2 - 4
y = (-2 + 1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3

For (0, -2), substitute x = 0 into the equation:
y = (2(0) + 1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3

For (1, 2), substitute x = 1 into the equation:
y = (2(1) + 1)^2 - 4
y = (2 + 1)^2 - 4
y = (3)^2 - 4
y = 9 - 4
y = 5

So, the only point on the graph described by the function is (1, 2).