Which of the following is a point on the graph as described by the function y = (2x + 1)² - 4? (1 point) O (-1, -3) O (-1,-5) O (1,2) (0, -2)

Answer 1

To find a point on the graph of the function, we can choose a value for x and substitute it into the equation to solve for y.

Let's try the point (-1, -3) first:

y = (2(-1) + 1)² - 4
y = ( -2 + 1 )² - 4
y = ( -1 )² - 4
y = 1 - 4
y = -3

So, (-1, -3) is a point on the graph of the function.

We can also check the other points:

For (-1, -5):

y = (2(-1) + 1)² - 4
y = ( -2 + 1 )² - 4
y = ( -1 )² - 4
y = 1 - 4
y = -3

(-1, -5) is not a point on the graph.

For (1, 2):

y = (2(1) + 1)² - 4
y = ( 2 + 1 )² - 4
y = ( 3 )² - 4
y = 9 - 4
y = 5

(1, 2) is not a point on the graph.

For (0, -2):

y = (2(0) + 1)² - 4
y = ( 0 + 1 )² - 4
y = ( 1 )² - 4
y = 1 - 4
y = -3

(0, -2) is not a point on the graph.

Therefore, the point (-1, -3) is on the graph as described by the function y = (2x + 1)² - 4.