To solve the equation \(3x^3 + 9x^2 - 54x = 0\), we start by factoring out the common term.
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Factor out \(3x\): \[ 3x(x^2 + 3x - 18) = 0 \]
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This gives us one solution: \[ 3x = 0 \implies x = 0 \]
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Now, we need to solve the quadratic equation \(x^2 + 3x - 18 = 0\). We can either factor it or use the quadratic formula.
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Attempting to factor: \[ x^2 + 3x - 18 = (x + 6)(x - 3) \] This gives us: \[ x + 6 = 0 \implies x = -6 \] and \[ x - 3 = 0 \implies x = 3 \]
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Thus, the complete set of solutions is: \[ x = 0, x = 3, x = -6 \]
Therefore, the correct answer is: \[ \boxed{0, 3, -6} \]