Nope.
∫ 1/(x^2+1) dx :: not so simple here. You need x = tanθ
The 2nd is the same, unless there are some groupings you have omitted.
∫ x/(x^2+1) dx :: u = x^2+1
∫ x^3/(x^4+1) dx :: u = x^4+1
Which of the following integrals cannot be evaluated using a simple substitution?
the integral of 1 divided by the quantity x squared plus 1, dx
the integral of 1 divided by the quantity x squared plus 1, dx
the integral of x divided by the quantity x squared plus 1, dx
(MY ANSWER)
the integral of x cubed divided by the quantity x to the 4th power plus 1, dx
3 answers
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BLM +VOTE+ COVID= hope yall have a nice life.
1 answer