Which of the following has the largest effective nuclear charge experienced by the valence electrons? *
A.O
B.C
C.Sn
D.Rb
3 answers
Is this B?
Are you supposed to do this as an estimate or are you to use Slater's Rule.
Zeff = Z - S where Z is the nuclear charge (the number of protons) and S is the shielding of the valence electrons from the nucleus. For the estimated number S is simply the number of inner electrons not in the valence shell and that's pretty easy to do. For a more accurate numbef for Zeff you can look up Slater's rule. There is a set protocol for doing this AND there is a formula for calculating based upon numbers supplied by Slater. For example an s electron use 0.5 but for a p electrons it's a different value. At any rate follow what you've been taught in your class. If you have trouble find info on Slater's Rule let me know and I'll look too.
Zeff = Z - S where Z is the nuclear charge (the number of protons) and S is the shielding of the valence electrons from the nucleus. For the estimated number S is simply the number of inner electrons not in the valence shell and that's pretty easy to do. For a more accurate numbef for Zeff you can look up Slater's rule. There is a set protocol for doing this AND there is a formula for calculating based upon numbers supplied by Slater. For example an s electron use 0.5 but for a p electrons it's a different value. At any rate follow what you've been taught in your class. If you have trouble find info on Slater's Rule let me know and I'll look too.
I'm thinking that probably is the simpler approach so I'll show those below.
Zeffective = Z - S where Z is the nuclear charge;i.e., the number of protons and S is the shielding; i.e., all of the electrons EXCEPT the outside one(s). So for 8O16, that is 1s2 2s2 2p4
Zeff = 8 - 2 = 6
6C is 1s2 2s2 2p2 so Zeff = 6 - 2 = 4
50Sn is [Kr] 4d10 5s2 5p2 Zeff = 50-(36+10) = 4
37Rb is [Kr] 5s1 Zeff = 37-36 = 1
Zeffective = Z - S where Z is the nuclear charge;i.e., the number of protons and S is the shielding; i.e., all of the electrons EXCEPT the outside one(s). So for 8O16, that is 1s2 2s2 2p4
Zeff = 8 - 2 = 6
6C is 1s2 2s2 2p2 so Zeff = 6 - 2 = 4
50Sn is [Kr] 4d10 5s2 5p2 Zeff = 50-(36+10) = 4
37Rb is [Kr] 5s1 Zeff = 37-36 = 1