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which of the following four equations has the solution of the lowest value?

x- 6= -16
x-7=28
x+19=-5
x+25-2

1 answer

Let's solve each equation one by one.

  1. Equation: \( x - 6 = -16 \)
    Adding 6 to both sides:
    \( x = -16 + 6 \)
    \( x = -10 \)

  2. Equation: \( x - 7 = 28 \)
    Adding 7 to both sides:
    \( x = 28 + 7 \)
    \( x = 35 \)

  3. Equation: \( x + 19 = -5 \)
    Subtracting 19 from both sides:
    \( x = -5 - 19 \)
    \( x = -24 \)

  4. Equation: \( x + 25 = 2 \) (assuming the equation should be \( x + 25 = 2 \) instead of \( x + 25 - 2 \))
    Subtracting 25 from both sides:
    \( x = 2 - 25 \)
    \( x = -23 \)

Now, we have the solutions:

  1. \( x = -10 \)
  2. \( x = 35 \)
  3. \( x = -24 \)
  4. \( x = -23 \)

Comparing the solutions, the lowest value is:
\( -24 \) from the equation \( x + 19 = -5 \).