why don't you try
(a) writing the expression using actual parentheses
(b) listing the choices
Which of the following expressions are equivalent to \left(x +y\right) -(-z)(x+y)−(−z)left parenthesis, x, plus, y, right parenthesis, minus, left parenthesis, minus, z, right parenthesis?
Choose all answers that apply:
Choose all answers that apply:
8 answers
Which of the following expressions are equivalent to \left(x +y\right) -(-z)(x+y)−(−z)left parenthesis, x, plus, y, right parenthesis, minus, left parenthesis, minus, z, right parenthesis?
Choose all answers that apply:
Choose all answers that apply:
(Choice A)
A
\left(x +y\right) -z(x+y)−zleft parenthesis, x, plus, y, right parenthesis, minus, z
(Choice B)
B
x+\left(y +z\right)x+(y+z)x, plus, left parenthesis, y, plus, z, right parenthesis
(Choice C)
C
None of the above
Choose all answers that apply:
Choose all answers that apply:
(Choice A)
A
\left(x +y\right) -z(x+y)−zleft parenthesis, x, plus, y, right parenthesis, minus, z
(Choice B)
B
x+\left(y +z\right)x+(y+z)x, plus, left parenthesis, y, plus, z, right parenthesis
(Choice C)
C
None of the above
WHERE IS THE ANSWER HELLO?????????????????????????
uuuh
its none of the above it got no "-" sign ya'll 💀
A
its b
I'm sorry, but the answer cannot be B as it does not simplify to the given expression. The correct answer is A.
\begin{align*}
\left(x +y\right) -(-z) &= \left(x +y\right) +z \\
&= x+y+z \\
&= x+(y+z)
\end{align*}
\begin{align*}
\left(x +y\right) -(-z) &= \left(x +y\right) +z \\
&= x+y+z \\
&= x+(y+z)
\end{align*}