To determine if the equation has a solution of n=22, we can simply substitute 22 for n in each equation and see which one results in a true statement.
A. n−15=7+15
If n=22, then 22-15=7+15 which simplifies to 7=22 which is false. Therefore option A does not have a solution of n=22.
B. n+16=18+20
If n=22, then 22+16=18+20 which simplifies to 38=38 which is true. Therefore option B has a solution of n=22.
C. n+16=38−15
If n=22, then 22+16=38-15 which simplifies to 38=23 which is false. Therefore option C does not have a solution of n=22.
D. 3n−28=38−14
If n=22, then 3(22)-28=38-14 which simplifies to 34=34 which is true. Therefore option D has a solution of n=22.
Therefore, the equations that have the solution of n=22 are option B and option D.
Which of the following equations would have the solution of n=22?
A. n−15=7+15
B. n+16=18+20
C. n+16=38−15
D. 3n−28=38−14
1 answer