Which of the following equations have solutions that are z=3 ?

Question

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​Select all that apply.(2 points)
Responses

9z−5=22
9z−5=22

54−8z=30
54−8z=30

9z+22=26
9z+22=26

5z+40=62
5z+40=62

Answer 1

To find out which equations have solutions that are z=3, we can substitute z=3 into each equation and see if it is true.

For the first equation, 9z - 5 = 22, substitute z=3:
9(3) - 5 = 27 - 5 = 22.
Since the equation is true, z=3 is a solution to this equation.

For the second equation, 54 - 8z = 30, substitute z=3:
54 - 8(3) = 54 - 24 = 30.
Since the equation is true, z=3 is a solution to this equation.

For the third equation, 9z + 22 = 26, substitute z=3:
9(3) + 22 = 27 + 22 = 49.
Since the equation is not true (49 ≠ 26), z=3 is not a solution to this equation.

For the fourth equation, 5z + 40 = 62, substitute z=3:
5(3) + 40 = 15 + 40 = 55.
Since the equation is not true (55 ≠ 62), z=3 is not a solution to this equation.

So, the equations that have solutions that are z=3 are:
- 9z - 5 = 22
- 54 - 8z = 30