Lets evaluate D
6y-2=2(y-1)
Now distribute the 2
6y-2=2y-2
Add two to both sides....in this case they cancel each other.
Now we have 6y=2y
The only number that will make this equal is 0. SO y=0 here.
So D cant be the answer.
Which of the following equations has an infinite number of solutions?
A. 3x-3=-4x
B. 2y+4-y=16
C. 7x+5=4x+5+3x
D. 6y-2=2(y-1)***
Is the answer D?
2 answers
Ok B then?