To determine which of the equations has a solution of -8, we can substitute -8 for \( x \) in each equation and check if it satisfies the equation.
-
Equation: \( x - 10 = 2 \) \[ -8 - 10 = -18 \quad (\text{not equal to } 2) \]
-
Equation: \( x + 3 = -11 \) \[ -8 + 3 = -5 \quad (\text{not equal to } -11) \]
-
Equation: \( x - 4 = -12 \) \[ -8 - 4 = -12 \quad (\text{equal to } -12) \]
-
Equation: \( x - 8 = 0 \) \[ -8 - 8 = -16 \quad (\text{not equal to } 0) \]
The only equation that has a solution of -8 is: \[ x - 4 = -12 \]