To determine which of the provided equations has a solution of \(-8\), we can substitute \(-8\) into each equation and check if it satisfies the equation.
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\(x - 10 = 2\)
Substitute \(-8\) for \(x\): \[ -8 - 10 = -18 \quad (\text{not } 2) \] -
\(x - 4 = -12\)
Substitute \(-8\) for \(x\): \[ -8 - 4 = -12 \quad (\text{this is correct}) \] -
\(x - 8 = 0\)
Substitute \(-8\) for \(x\): \[ -8 - 8 = -16 \quad (\text{not } 0) \] -
\(x + 3 = -11\)
Substitute \(-8\) for \(x\): \[ -8 + 3 = -5 \quad (\text{not } -11) \]
The equation that has a solution of \(-8\) is:
\(x - 4 = -12\).