To check which equation has a solution of \( x = -\frac{1}{2} \), we can substitute \(-\frac{1}{2}\) into each equation and see if they hold true.
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Equation: \( x - 1 = -\frac{1}{2} \) \[ -\frac{1}{2} - 1 = -\frac{1}{2} \quad \text{(Not true, as } -\frac{3}{2} \neq -\frac{1}{2}) \]
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Equation: \( x + \frac{1}{2} = -1 \) \[ -\frac{1}{2} + \frac{1}{2} = -1 \quad \text{(Not true, as } 0 \neq -1) \]
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Equation: \( x - \frac{1}{2} = 1 \) \[ -\frac{1}{2} - \frac{1}{2} = 1 \quad \text{(Not true, as } -1 \neq 1) \]
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Equation: \( x + 1 = \frac{1}{2} \) \[ -\frac{1}{2} + 1 = \frac{1}{2} \quad \text{(True, as } \frac{1}{2} = \frac{1}{2}) \]
The equation that has a solution of \( -\frac{1}{2} \) is:
\( x + 1 = \frac{1}{2} \)