To determine which equation has a solution of \( -\frac{1}{2} \), we can substitute \( x = -\frac{1}{2} \) into each equation and see which one balances.
-
Equation: \( x - \frac{1}{2} = 1 \)
Substitute \( x = -\frac{1}{2} \): \[ -\frac{1}{2} - \frac{1}{2} = 1 \implies -1 = 1 \quad \text{(not true)} \]
-
Equation: \( x + \frac{1}{2} = -1 \)
Substitute \( x = -\frac{1}{2} \): \[ -\frac{1}{2} + \frac{1}{2} = -1 \implies 0 = -1 \quad \text{(not true)} \]
-
Equation: \( x - 1 = -\frac{1}{2} \)
Substitute \( x = -\frac{1}{2} \): \[ -\frac{1}{2} - 1 = -\frac{1}{2} \implies -\frac{3}{2} = -\frac{1}{2} \quad \text{(not true)} \]
-
Equation: \( x + 1 = \frac{1}{2} \)
Substitute \( x = -\frac{1}{2} \): \[ -\frac{1}{2} + 1 = \frac{1}{2} \implies \frac{1}{2} = \frac{1}{2} \quad \text{(true)} \]
The equation that has a solution of \( -\frac{1}{2} \) is:
\( x + 1 = \frac{1}{2} \).