To determine which equation has a solution of \( x = -\frac{1}{2} \), we can test each equation by substituting \( -\frac{1}{2} \) for \( x \).
-
\( x + 12 = -1 \)
\(-\frac{1}{2} + 12 = -1\)
\(11.5 \neq -1\) (not a solution) -
\( x + \frac{1}{2} = -1 \)
\(-\frac{1}{2} + \frac{1}{2} = -1\)
\(0 \neq -1\) (not a solution) -
\( x - 12 = 1 \)
\(-\frac{1}{2} - 12 = 1\)
\(-12.5 \neq 1\) (not a solution) -
\( x - \frac{1}{2} = 1 \)
\(-\frac{1}{2} - \frac{1}{2} = 1\)
\(-1 \neq 1\) (not a solution) -
\( x + 1 = 12 \)
\(-\frac{1}{2} + 1 = 12\)
\(\frac{1}{2} \neq 12\) (not a solution) -
\( x - 1 = -12 \)
\(-\frac{1}{2} - 1 = -12\)
\(-1.5 \neq -12\) (not a solution)
None of the equations listed seem to have \(-\frac{1}{2}\) as a solution. Could there be a misunderstanding or a missing equation in your options? Please double-check the equations or provide more context.