To determine which equation has a solution different from the others, we need to solve each equation and find their respective solutions.
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Equation 1: \(-17x - 34 = 14\)
\(-17x = 14 + 34\)
\(-17x = 48\)
\(x = \frac{48}{-17}\)
\(x = -\frac{48}{17}\) -
Equation 2: \(-\frac{1}{7}x - \frac{3}{4} = \frac{1}{4}\)
\(-\frac{1}{7}x = \frac{1}{4} + \frac{3}{4}\)
\(-\frac{1}{7}x = 1\)
\(x = -7\) -
Equation 3: \(-0.35x - 0.52 = 1.93\)
\(-0.35x = 1.93 + 0.52\)
\(-0.35x = 2.45\)
\(x = \frac{2.45}{-0.35}\)
\(x = -7\) -
Equation 4: \(12x - 3 = 12\)
\(12x = 12 + 3\)
\(12x = 15\)
\(x = \frac{15}{12}\)
\(x = \frac{5}{4}\) -
Equation 5: \(34x + 5 = -14\)
\(34x = -14 - 5\)
\(34x = -19\)
\(x = \frac{-19}{34}\)
Now, let's summarize the solutions:
- \(x = -\frac{48}{17}\)
- \(x = -7\)
- \(x = -7\)
- \(x = \frac{5}{4}\)
- \(x = \frac{-19}{34}\)
From this analysis, we see:
- Equations 2 and 3 both have the solution \(x = -7\).
- Equation 4 has a unique solution \(x = \frac{5}{4}\).
- Equations 1 and 5 yield different unique results.
However, the distinct solution can be identified among the options. Based on the values computed:
- Equation 4's solution \(x = \frac{5}{4}\) is different from the others.
Therefore, the equation with a solution different from the rest is: 12x − 3 = 12.