To determine which equation has a solution different from the rest, we can solve each equation for \( x \).
-
Equation 1:
\(-0.35x - 0.52 = 1.93\)
\(-0.35x = 1.93 + 0.52\)
\(-0.35x = 2.45\)
\(x = \frac{2.45}{-0.35}\)
\(x \approx -7\) -
Equation 2:
\(\frac{1}{2}x - 3 = \frac{1}{2}\)
\(\frac{1}{2}x = \frac{1}{2} + 3\)
\(\frac{1}{2}x = \frac{1}{2} + \frac{6}{2}\)
\(\frac{1}{2}x = \frac{7}{2}\)
\(x = 7\) -
Equation 3:
\(-\frac{1}{7}x - \frac{3}{4} = \frac{1}{4}\)
\(-\frac{1}{7}x = \frac{1}{4} + \frac{3}{4}\)
\(-\frac{1}{7}x = 1\)
\(x = -7\) -
Equation 4:
\(\frac{3}{4}x + 5 = -\frac{1}{4}\)
\(\frac{3}{4}x = -\frac{1}{4} - 5\)
\(\frac{3}{4}x = -\frac{1}{4} - \frac{20}{4}\)
\(\frac{3}{4}x = -\frac{21}{4}\)
\(x = -7\)
Now, we summarize the solutions we found:
- \( x \approx -7 \)
- \( x = 7 \)
- \( x = -7 \)
- \( x = -7 \)
The equation with a solution different from the rest is Equation 2, which has the solution \( x = 7 \), while the others have the solution \( x \approx -7 \).