Let's solve each equation to determine the value of \( x \) for each, and find which one has a different value.
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Equation 1: \( x - 78 = -32 \)
\[ x = -32 + 78 = 46 \]
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Equation 2: \( x - \frac{7}{8} = -\frac{3}{2} \)
To solve for \( x \):
\[ x = -\frac{3}{2} + \frac{7}{8} \] Converting \(-\frac{3}{2}\) to have a denominator of 8: \(-\frac{3}{2} = -\frac{12}{8}\)
\[ x = -\frac{12}{8} + \frac{7}{8} = -\frac{5}{8} \]
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Equation 3: \( x + 0.875 = 1.5 \)
\[ x = 1.5 - 0.875 = 0.625 \]
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Equation 4: \( x + 98 = 74 \)
\[ x = 74 - 98 = -24 \]
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Equation 5: \( x - 0.025 = 0.6 \)
\[ x = 0.6 + 0.025 = 0.625 \]
Now we have the values of \( x \) for each equation:
- \( x = 46 \)
- \( x = -\frac{5}{8} \) (or -0.625)
- \( x = 0.625 \)
- \( x = -24 \)
- \( x = 0.625 \)
Among these values, \( 46 \), \( -\frac{5}{8} \), and \( -24 \) are different from the others, but \( x = 0.625 \) appears twice.
Thus, the equation that has a different value of \( x \) than the others is:
Equation 1: \( x - 78 = -32 \) with \( x = 46 \).