The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction. This means that the number of atoms of each element must be the same on both sides of the equation.
Let's examine each option:
A. \( CH_4 + O_2 \rightarrow C + 2H_2O \)
- Left: 1 C, 4 H, 2 O
- Right: 1 C, 4 H, 2 O
- Conservation of mass is satisfied.
B. \( CH + O_2 \rightarrow CO_2 + H_2O \)
- Left: 1 C, 1 H, 2 O
- Right: 1 C, 2 H, 3 O
- Conservation of mass is not satisfied.
C. \( CH_4 + O_2 \rightarrow CO_2 + HO \)
- Left: 1 C, 4 H, 2 O
- Right: 1 C, 4 H, 3 O
- Conservation of mass is not satisfied. (There should be \( H_2O \) instead of \( HO \))
D. \( CH_4 + O_2 \rightarrow CO_2 + H_2O \)
- Left: 1 C, 4 H, 2 O
- Right: 1 C, 2 H, 3 O
- Conservation of mass is not satisfied. (This should balance as \( CH_4 + 2O_2 \) to have 4 H on both sides)
Among these options, A is the only equation that correctly demonstrates the law of conservation of mass.