To transform the function \( f(x) = x^2 + 9 \) to \( f(2x + 1) \) and then evaluate it at \( x = 2 \), follow these steps:
- Substitute \( 2x + 1 \) in place of \( x \) in the function \( f(x) \):
\[ f(2x + 1) = (2x + 1)^2 + 9 \]
- Expand \( (2x + 1)^2 \):
\[ (2x + 1)^2 = 4x^2 + 4x + 1 \]
So we have:
\[ f(2x + 1) = 4x^2 + 4x + 1 + 9 = 4x^2 + 4x + 10 \]
- Now, evaluate \( f(2x + 1) \) at \( x = 2 \):
\[ f(2(2) + 1) = f(5) = 4(2^2) + 4(2) + 10 \]
Calculating that:
\[ f(5) = 4(4) + 8 + 10 = 16 + 8 + 10 = 34 \]
Therefore, the correct transformation gives us \( f(2x + 1) = 34 \) when evaluated at \( x = 2 \).
The correct response is 34.