To solve the equation \( \ln(3) = \ln(12 - 12x) \), we can use the property of logarithms that states if \( \ln(a) = \ln(b) \), then \( a = b \).
So we can set the arguments equal to each other:
\[ 3 = 12 - 12x \]
Now, let's solve for \( x \):
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Subtract 12 from both sides: \[ 3 - 12 = -12x \] \[ -9 = -12x \]
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Divide both sides by -12: \[ x = \frac{-9}{-12} = \frac{9}{12} = \frac{3}{4} \]
So, the solution to the equation is:
\[ x = \frac{3}{4} \]
The correct response is:
x equals Start Fraction 3 over 4 End Fraction