The phase shift of the function \( f(x) = 2 \sin(x + \frac{\pi}{6}) \) can be determined from the expression inside the sine function. In the general form of a sine function \( f(x) = a \sin(b(x - c)) + d \), the phase shift is given by \( c \), where \( c \) is derived from the equation \( x + \frac{\pi}{6} = 0 \).
To find \( c \):
- Rewrite \( x + \frac{\pi}{6} \) as \( x - (-\frac{\pi}{6}) \).
- This indicates that the phase shift is \( -\frac{\pi}{6} \).
Therefore, the correct response that describes the phase shift is:
−π/6 (negative pi over 6).