The Commutative Property of Multiplication states that changing the order of the factors does not change the product. In other words, for any numbers \( a \) and \( b \), \( a \times b = b \times a \).
Let's analyze each option:
A. \( 11(b+z) = 11b + 11z \) - This demonstrates the Distributive Property, not the Commutative Property.
B. \( z^{11} \cdot 2 = z^{11} + 2 \) - This is incorrect because multiplication does not equal addition in this context.
C. \( 3(b^{10}+4) = 3(4+b^{10})3 \) - This is incorrect as it appears to be miswritten, plus it does not effectively express the Commutative Property.
D. \( 2(b^{10}+z^{11}) = (b^{10}+z^{11}) \cdot 2 \) - This demonstrates the Commutative Property because it shows that the order of multiplying \( 2 \) and the expression \( (b^{10}+z^{11}) \) does not affect the result.
The correct option that demonstrates the use of the Commutative Property of Multiplication is:
D. 2(b^10+z^11)=(b^10+z^11)•2
2 answers