The Commutative Property of Multiplication states that the order in which two numbers are multiplied does not change the product. This can be expressed as \( a \times b = b \times a \) for any numbers \( a \) and \( b \).
Looking at the provided options:
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\( 11(b+z) = 11b + 11z \) - This demonstrates the Distributive Property, not the Commutative Property.
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\( 3(b^{10}+4) = 3(4+b^{10}) \) - This demonstrates the Commutative Property of Addition inside the parentheses but not the Commutative Property of Multiplication.
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\( z^{11} \cdot 2 = z^{11} + 2 \) - This is incorrect because multiplication is being incorrectly expressed as addition.
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\( 2(b^{10}+z^{11}) = (b^{10}+z^{11}) \cdot 2 \) - This demonstrates the Commutative Property of Multiplication because it shows that changing the order of multiplication does not change the result.
Therefore, the correct demonstration of the Commutative Property of Multiplication is:
\( 2(b^{10}+z^{11}) = (b^{10}+z^{11}) \cdot 2 \).