The Commutative Property of Multiplication states that the order in which two numbers are multiplied does not change the product. In other words, \( a \times b = b \times a \).
Let's analyze each option:
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\( 11(b + z) = 11b + 11z \) - This represents the Distributive Property, not the Commutative Property.
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\( 2(b^{10} + z^{11}) = (b^{10} + z^{11}) \cdot 2 \) - This also illustrates the Commutative Property as it shows that multiplying by \( 2 \) can be done in either order.
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\( 3(b^{10}+4) = 3(4+b^{10}) \) - This is a correct use of the Commutative Property as well, since it shows that the expression inside the parentheses can be rearranged.
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\( z^{11} \cdot 2 = z^{11} + 2 \) - This is incorrect as the operations are not correctly illustrated.
Therefore, the options that demonstrate the use of the Commutative Property of Multiplication are options 2 and 3. However, specifically for identifying the "use" of the Commutative Property prominently, option 3 is the clearest demonstration of the property.
Final answer: 3(b^{10}+4) = 3(4+b^{10})