To determine which of the given coordinate pairs is a point on the parabola y=7x^2+32x-19, substitute the x-coordinate into the equation and check if it satisfies the equation by computing the corresponding y-coordinate.
Let's test each coordinate pair (x, y) given:
1. (-2, -3):
Substituting x = -2 into the equation:
y = 7(-2)^2 + 32(-2) - 19
y = 7(4) - 64 - 19
y = 28 - 64 - 19
y = -55
The computed y-coordinate is -55, which does not match the given y-coordinate -3. Therefore, (-2, -3) is not a point on the parabola.
2. (0, -19):
Substituting x = 0 into the equation:
y = 7(0)^2 + 32(0) - 19
y = 0 + 0 - 19
y = -19
The computed y-coordinate is -19, which matches the given y-coordinate -19. Thus, (0, -19) is a point on the parabola.
3. (1, 20):
Substituting x = 1 into the equation:
y = 7(1)^2 + 32(1) - 19
y = 7 + 32 - 19
y = 20
The computed y-coordinate is 20, which matches the given y-coordinate 20. Therefore, (1, 20) is a point on the parabola.
Hence, the point on the parabola is (0, -19) and (1, 20).
Which of the following coordinate pairs is a point on the parabola
y=7x^2+32x-19
1 answer
1 answer