In the expression \( su + 1 + s + 6st \), the terms are the individual components separated by addition or subtraction.
The terms in the expression are:
- \( su \)
- \( 1 \)
- \( s \)
- \( 6st \)
Now, let's evaluate the options you've provided:
- 6st - This is a term in the expression (yes).
- T - This is not a term in the expression (no).
- 6t - This is also not a term in the expression (no).
- S - This is not a term in the expression; it is just represented by a lowercase 's' (no).
From these analyses, the only option that is a term in the expression is 6st.