Which of the following are most likely to form a stable ionic bond

A) Carbon (Period IVA) and Oxygen (Period VIA)
B) Lithium (Period IA) and Fluorine (Period VIIA)
C) Magnesium (Period IIA) and Iron (Period VIIIB)
D) Potassium (Period IA) and Tin (Period IVA)

1 answer

Ionic bonds are typically formed between metals and nonmetals, where one atom donates an electron (usually a metal) and the other atom accepts that electron (usually a nonmetal). To assess the options:

A) Carbon (Period IVA) and Oxygen (Period VIA) - Both carbon and oxygen are nonmetals. They can form covalent bonds but are less likely to form a stable ionic bond.

B) Lithium (Period IA) and Fluorine (Period VIIA) - Lithium is a metal and fluorine is a nonmetal. Lithium can donate one electron, and fluorine can accept that electron, forming a stable ionic bond (LiF).

C) Magnesium (Period IIA) and Iron (Period VIIIB) - Both magnesium and iron are metals. They typically do not form ionic bonds with each other.

D) Potassium (Period IA) and Tin (Period IVA) - Potassium is a metal and tin is a metalloid; however, they typically do not form a stable ionic bond.

Given these assessments, the pair that is most likely to form a stable ionic bond is:

B) Lithium (Period IA) and Fluorine (Period VIIA).

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