To find which of the first 10 natural numbers is not a solution of 5x - 1 ≠ 9, we can solve the inequality for each number and see if it satisfies the inequality.
Let's check the numbers one by one:
For x = 1:
5(1) - 1 ≠ 9
5 - 1 ≠ 9
4 ≠ 9
Since 4 is not equal to 9, x = 1 is a solution.
For x = 2:
5(2) - 1 ≠ 9
10 - 1 ≠ 9
9 ≠ 9
Since 9 is not equal to 9, x = 2 is a solution.
For x = 3:
5(3) - 1 ≠ 9
15 - 1 ≠ 9
14 ≠ 9
Since 14 is not equal to 9, x = 3 is a solution.
For x = 4:
5(4) - 1 ≠ 9
20 - 1 ≠ 9
19 ≠ 9
Since 19 is not equal to 9, x = 4 is a solution.
For x = 5:
5(5) - 1 ≠ 9
25 - 1 ≠ 9
24 ≠ 9
Since 24 is not equal to 9, x = 5 is a solution.
For x = 6:
5(6) - 1 ≠ 9
30 - 1 ≠ 9
29 ≠ 9
Since 29 is not equal to 9, x = 6 is a solution.
For x = 7:
5(7) - 1 ≠ 9
35 - 1 ≠ 9
34 ≠ 9
Since 34 is not equal to 9, x = 7 is a solution.
For x = 8:
5(8) - 1 ≠ 9
40 - 1 ≠ 9
39 ≠ 9
Since 39 is not equal to 9, x = 8 is a solution.
For x = 9:
5(9) - 1 ≠ 9
45 - 1 ≠ 9
44 ≠ 9
Since 44 is not equal to 9, x = 9 is a solution.
For x = 10:
5(10) - 1 ≠ 9
50 - 1 ≠ 9
49 ≠ 9
Since 49 is not equal to 9, x = 10 is a solution.
Therefore, none of the first 10 natural numbers are solutions to the inequality 5x - 1 ≠ 9.
Which of the first 10 natural numbers is NOT a solution of 5x -1 ≠9?
2 answers
yo bot is wrong its 2